Python list Interview Q&A

 #----------------List Interview Question For Zero to Adv Level--------

# Reverse a list

number=[10,30,20,40,60,90,80,100]

# using sort and reverse keyword we can use

number.sort(reverse=True)

print(number) # result [100, 90, 80, 60, 40, 30, 20, 10]

number1=[10,30,20,40,60,90,80,100]

#without Sort and reverse key word

print(number1[::-1]) #result [100, 80, 90, 60, 40, 20, 30, 10]

#2. Find largest & smallest

number2=[10,30,20,40,60,90,80,100]

print(max(number2)) # Max Number is 100

print(min(number2)) # Min Number is 10

print(sum(number2)) # Sum of Number is 430

#3.Count occurrences

number2=[10,30,20,40,20,20,20,60,90,80,100]

print(number2.count(20)) # Result is 4

#4.Remove duplicates

print(list(set(number2))) #[100, 40, 10, 80, 20, 90, 60, 30]

#5 Second_largest number in list

L1=list(set(number2)) # Remove Duplicates

L1.sort() # sort the List

print(L1[-2]) # Find the Second_Highest Number

mylist = ['apple', 'banana', 'cherry']

mylist[1:2] = ['kiwi', 'mango']

print(mylist) 

print(mylist[2])